They fail with the error "The add-on could not be downloaded because of a connection failure."
#Firefox developer edition forums install
However, it turns out that there is a problem - when "_mozAddonManager" is set to True, you can't install addons from.
In order to allow extensions to work on this protected site, you have to do the following in about:config:
#Firefox developer edition forums portable
It is not a well formed question, but I nevertheless am in search of a better explanation for this specific part of the problem.I'm using Firefox Developer Edition v79, and I've been getting plagued by a particular issue for a while, but only recently found a bug report that clued me into the cause - and it's specific to the portable version only.įirefox prohibits extensions from working on their own site (specifically, ). This is what I told my student, and he then asked how that can work. There is only one possible answer, given that the wheel is only in contact with the rod, and that is that the rod somehow provides an upwards force as well as a centripetal force.
But in order for the wheel to only precess, and not fall, there must be an upwards force balancing out the weight of the wheel. There is a centripetal force, supplied by the rod, and the weight of the wheel. Let's just take the wheel itself (not the rod). We know that if you analyse any part of the system separately, the forces on the centre of mass must be in the same direction as the acceleration of the centre of mass. However, one of my students (who is below uni level) recently asked me a basic question about the system, and I was embarassed to realise that I didn't have a good answer for him. With higher concepts like angular momentum, it is fairly straightforward to explain the motion. This is a standard problem in university physics, which I studied at university in depth. If the former, then surely a high-frequency wave must actually be traveling faster than the speed of light, in order to take its rollercoaster-y path and still get somewhere just as quick as a wave traveling at the speed of light and taking a flatter path through space.īnosnehpets Asks: Gyroscopic bicycle wheel - forces on the wheel only If the latter, then I assume we conclude that some electromagnetic waves get to a destination faster than others (specifically, low-frequency waves get there quicker). So my question is: what does "speed" mean in the context of electromagnetic waves? Is it the time to go from A to B? Or is it the actual speed of the wave, on its up-and-down curved trajectory? If we define the speed of the plane just in terms of the time it took to get from the starting point to the finishing point, the speed of the two planes is different - the plane with the rollercoaster-style trajectory takes longer. If we define the speed of the plane in terms of how fast it is moving, the speed of the two planes is the same.
A plane flying at a given velocity X on a flat trajectory will get from Kansas to New York in less time than a plane flying at the same velocity X on a rollercoaster-esque trajectory. If #2 doesn't seem like a valid possibility, let me explain my reasoning.
Waves of all frequencies move at the same speed, but those of higher frequencies take longer to get somewhere. Waves of all frequencies get from A to B in the same time. Which of the following interpretations of this is correct: Starting point: "electromagnetic waves of all frequencies travel through space at the same fixed speed - the speed of light". Teby94 Asks: How do all elecromagnetic waves travel at the same speed, if some have shorter wavelengths and therefore take a more circuitous route from A to B?
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